Bantu kakkk✨✨✨
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Sertakan langkah-langkahnya, terimakasih ✨
*soal tertera digambar
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Sertakan langkah-langkahnya, terimakasih ✨
*soal tertera digambar
2. [tex]\lim_{x \to 1} (x-3)=1-3=2[/tex]
3. [tex]\lim_{x \to 2} (2x^2-x-4)=2(2)^2-(2)-4=2(4)-6=2[/tex]
4. [tex]\lim_{x \to 4}\frac{x-4}{\sqrt{x}-2 }= \lim_{x \to 4}\frac{x-4}{\sqrt{x}-2 }.\frac{\sqrt{x}+2}{\sqrt{x}+2}[/tex]
[tex]=\lim_{x \to 4}\frac{(x-4)(\sqrt{x}+2)}{(x-4)} \\=\lim_{x \to 4}(\sqrt{x}+2)\\ =\sqrt{4}+2\\ =2+2\\=4[/tex]
5. [tex]\lim_{x \to 2} \frac{x^2-4}{x^4-16} = \lim_{x \to 2} \frac{x^2-4}{(x^2-4)(x^2+4)}[/tex]
[tex]=\lim_{x \to 2} \frac{1}{x^2+4} \\=\frac{1}{2^2+4}\\=\frac{1}{4+4}\\=\frac{1}{8}[/tex]
[answer.2.content]
